Advanced level

Reading properties from a graph

A graph shows the whole function at once: domain and range, zeros, sign, intervals of monotonicity and the extremum. Learn to read them off the drawing before you compute anything.

Before you start

This topic builds on earlier ideas. Before you start, it's worth working through the lessons below — they'll make everything click:

All formulas

  • A zero

    f(x0)=0f(x_0) = 0

    where the graph crosses the x-axis

  • The sign of a function

    f(x)>0    graph above the x-axisf(x) > 0 \iff \text{graph above the } x\text{-axis}

    below the axis the values are negative

  • Increasing function

    x1<x2    f(x1)<f(x2)x_1 < x_2 \implies f(x_1) < f(x_2)

    on an interval where the graph rises

  • Decreasing function

    x1<x2    f(x1)>f(x2)x_1 < x_2 \implies f(x_1) > f(x_2)

    on an interval where the graph falls

  • Minimum

    f(x)f(xmin) for every xf(x) \geq f(x_{\min}) \ \text{for every } x

    the lowest point of the graph; a maximum works the same way

  • Domain and range

    Dfx-axis,Rfy-axisD_f \to x\text{-axis}, \quad R_f \to y\text{-axis}

    the shadows of the graph on the two axes

A graph carries all the information about a function at once. Before computing anything, six things can be read off it: the domain, the range, the zeros, the sign, the intervals of monotonicity and the extremum.

−3−2−1012345−5−4−3−2−1012345xyy = −4x₁ = −1x₂ = 3min = −4f(x) = x² − 2x − 3
The graph we keep coming back to: zeros −1 and 3, a minimum of −4 at x = 1.

Domain and range

Both are read as shadows of the graph on the axes:

  • the domain — the shadow on the horizontal axis: every argument for which something is drawn;
  • the range — the shadow on the vertical axis: every height at which the graph appears.

The parabola above stretches left and right without end, so its domain is every real number. Vertically, though, it only starts at the height 4-4 and goes up — below the dashed guide there is not a single point of the graph:

Df=R,Rf=4,+)D_f = \mathbb{R}, \qquad R_f = \langle -4, +\infty)

The zeros

A zero is an argument whose value is zero — on the graph, a crossing with the xx-axis:

f(x0)=0f(x_0) = 0

Our parabola crosses the horizontal axis at (1,0)(-1, 0) and (3,0)(3, 0), so the zeros are the numbers 1-1 and 33. Note that a zero is the x-coordinate, the bare number 1-1, and not the pair (1,0)(-1, 0).

The sign of a function

The sign is read off the position of the graph relative to the horizontal axis:

−1012345−4−20246xyx₀ = 2f(x) = −2x + 4
A decreasing function changes sign at its zero: positive to the left of x = 2, negative to the right.
  • graph above the axis f(x)>0\Rightarrow f(x) > 0;
  • graph below the axis f(x)<0\Rightarrow f(x) < 0;
  • graph on the axis f(x)=0\Rightarrow f(x) = 0.

The boundaries of the sign intervals are always the zeros — only there can the graph cross from one side of the axis to the other. For the line above f(x)>0f(x) > 0 for x<2x < 2 and f(x)<0f(x) < 0 for x>2x > 2; for an increasing function it would be exactly the other way round.

Read the sign of f(x) = x² − 2x − 3 off the first graph.

Monotonicity

A function is increasing on an interval when a larger argument has a larger value there:

x1<x2    f(x1)<f(x2)x_1 < x_2 \implies f(x_1) < f(x_2)

and decreasing when a larger argument has a smaller value:

x1<x2    f(x1)>f(x2)x_1 < x_2 \implies f(x_1) > f(x_2)

On the drawing it is enough to scan from left to right: where the graph rises, the function increases; where it falls, it decreases. Our parabola decreases on (,1(-\infty, 1\rangle and increases on 1,+)\langle 1, +\infty) — the boundary is the first coordinate of the vertex.

Two traps of language. First, monotonicity is stated for an interval, never for a single point: with this definition, "does the function increase at x=4x = 4?" is not a meaningful question. Second, "monotonic" does not mean "increasing" — a decreasing function is monotonic too, because it keeps changing in one direction.

The extremum

An extremum is a turning point: where the function stops decreasing and starts increasing (a minimum) or the other way round (a maximum). On the graph it is a valley or a hump.

The value of the extremum is the height of that point, not its xx-coordinate. For our parabola the minimum is 4-4 and it is attained at the argument 11 — two different numbers, and mixing them up is the commonest mistake in this lesson.

From the first graph read: the value f(0), the intervals of monotonicity, the extremum and the range.

Value and preimage

The two commonest "pointwise" questions are read along the same path, travelled in opposite directions:

  • the value — from the argument on the horizontal axis up to the graph, then across to the vertical axis;
  • the preimage — from the value on the vertical axis across to the graph, then down to the horizontal axis.

The difference matters: the value is one (that is the definition of a function), but the same value may be taken by several arguments. On our parabola the value 00 is reached twice and the value 4-4 only once.

Why read a graph when you can compute

Because computation delivers the properties one at a time, while the drawing shows them all at once. The number of zeros, the sign, the direction of change and the position of the extremum are visible before the delta is computed.

A graph is also the cheapest check on a result: if the computation gave a minimum of 22 while the drawn curve dips below zero, something is wrong. It works both ways — which is why a sketch is worth making even when a problem does not ask for one.

The reading has a limit, though: the drawing shows only the part of the domain that fitted into the frame. If the axis stops at x=5x = 5, the graph says nothing about what happens further out — and that is exactly when we go back to the formula.

Exercises

The questions cover three properties this lesson reads off a drawing but which have to be verified by computation: the zeros of a quadratic function, the value of its extremum, and the sign of a linear function. Type the zeros separated by a comma (-1, 3), and the sign as an inequality in the unknown, e.g. x > 2.

Practice

Work through a set of exercises — they get harder as you go. At the end you'll see your score and the mistakes worth reviewing.

Exercise 1 of 8Score: 0
x² − 8x + 12 = 0

Common mistakes

  • Giving a point instead of a zero — the zero is the number 1-1, not the pair (1,0)(-1, 0).
  • Confusing the value of an extremum with its argument — the minimum is 4-4, attained at x=1x = 1.
  • Swapping domain and range — the domain is the shadow on the horizontal axis, the range on the vertical one.
  • Monotonicity at a point — increasing and decreasing are properties of an interval.
  • Treating "monotonic" as "increasing" — a decreasing function is monotonic too.
  • Reading the sign without the zeros — they are what bounds the sign intervals.

Formula card

Topic: Reading properties from a graph

  • A zero

    f(x0)=0f(x_0) = 0

    where the graph crosses the x-axis

  • The sign of a function

    f(x)>0    graph above the x-axisf(x) > 0 \iff \text{graph above the } x\text{-axis}

    below the axis the values are negative

  • Increasing function

    x1<x2    f(x1)<f(x2)x_1 < x_2 \implies f(x_1) < f(x_2)

    on an interval where the graph rises

  • Decreasing function

    x1<x2    f(x1)>f(x2)x_1 < x_2 \implies f(x_1) > f(x_2)

    on an interval where the graph falls

  • Minimum

    f(x)f(xmin) for every xf(x) \geq f(x_{\min}) \ \text{for every } x

    the lowest point of the graph; a maximum works the same way

  • Domain and range

    Dfx-axis,Rfy-axisD_f \to x\text{-axis}, \quad R_f \to y\text{-axis}

    the shadows of the graph on the two axes

−3−2−1012345−5−4−3−2−1012345xyy = −4x₁ = −1x₂ = 3min = −4f(x) = x² − 2x − 3
The parabola y = x² − 2x − 3: zeros −1 and 3, a minimum of −4, and a horizontal guide marking the boundary of the range.
−1012345−4−20246xyx₀ = 2f(x) = −2x + 4
The sign of the decreasing function f(x) = −2x + 4: above the axis for x < 2, below it for x > 2. The boundary is the zero.

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