Intermediate level

Inverse proportion and the homographic function

The faster you drive, the shorter the drive — and the product of speed and time stays put. See how inverse proportion differs from direct, what the hyperbola y = a/x looks like, where its two asymptotes come from, and how to read them off a quotient of two linear expressions.

Before you start

This topic builds on earlier ideas. Before you start, it's worth working through the lessons below — they'll make everything click:

Where this is used

Real situations where you count exactly the way this lesson teaches:

  • Travel time
    The Warsaw–Kraków route is about 295 km, so the driving time is t = 295/v — inverse proportion in its purest form. At 90 km/h that is 3 h 17 min, at 120 km/h only 2 h 28 min. Doubling the speed from 100 to 200 km/h would cut the drive from 2 h 57 min to 1 h 29 min, exactly in half — and that is the whole content of the word "inverse".
  • Boyle's law
    At a constant temperature the product of a gas pressure and its volume is fixed: p·V = const. A 12-litre diving cylinder filled to 200 bar holds air that at 1 bar would occupy 2400 litres. At a depth of 30 m, where the pressure is 4 bar, the same supply lasts for 600 litres of breathing — four times less than at the surface.
  • Bicycle gearing
    The product of a sprocket tooth count and its rotational speed is constant, so the rear wheel turns at n = 52·80/z, where z is the rear tooth count and 80 the pedalling cadence. On a 13-tooth sprocket that is 320 revolutions per minute, on a 26-tooth one only 160 — a mechanic picks a cassette by computing exactly this hyperbola.
  • Splitting a cost across a team
    Renting a workshop room costs 1800 zloty, so the cost per head is k = 1800/n. With 6 participants that is 300 zloty, with 12 it is 150, with 24 it is 75. The curve falls ever more slowly: going from 6 to 12 people saves 150 zloty a head, going from 12 to 24 saves only 75 — so the organiser can see where adding participants stops paying off.

All formulas

  • Inverse proportion

    y=ax,a0y = \frac{a}{x}, \qquad a \neq 0

    domain: x \neq 0

  • The proportionality condition

    xy=ax \cdot y = a

    the product is constant — that is how a is found

  • Homographic function

    y=axp+qy = \frac{a}{x - p} + q

    a hyperbola translated by [p,\, q]

  • The asymptotes

    x=p,y=qx = p, \qquad y = q

    vertical and horizontal — approached, never reached

  • Vertex form

    ax+bxp=ap+bxp+a\frac{ax + b}{x - p} = \frac{ap + b}{x - p} + a

    a quotient of linear expressions as a translated hyperbola

There is a trip next week and 240 crates to move. One lorry takes them all, two take 120 each, four take 60 each. The product stays the same even though both factors change. That is inverse proportion.

Direct or inverse

Two quantities can be tied together in two opposite ways, and mixing them up is the commonest mistake in word problems.

direct proportioninverse proportion
what is constantyx=a\dfrac{y}{x} = axy=ax \cdot y = a
formulay=axy = axy=axy = \dfrac{a}{x}
twice the xxtwice the yyhalf the yy
grapha line through (0,0)(0,\,0)a hyperbola
examplethe price of nn kilogramsthe driving time at speed vv

Proportions and scale has a lesson of its own; here only the second column matters — and the function it describes.

The hyperbola y = a/x

y=ax,a0y = \frac{a}{x}, \qquad a \neq 0

The domain is every real number except zero, because dividing by zero is impossible. That single exclusion explains the entire shape of the graph.

−8−6−4−202468−8−6−4−202468xyy = 6/x
The hyperbola y = 6/x. Two branches split by the excluded zero, with the axes as its asymptotes — the curve gets arbitrarily close to them and never touches.

The curve has two branches, because the excluded zero cuts the argument axis in two with no crossing between them. For a>0a > 0 the branches sit in the first and third quadrants, for a<0a < 0 in the second and fourth.

The constant from a single point

Since y=axy = \tfrac{a}{x}, multiplying both sides by xx gives

a=xya = x \cdot y

The product of the coordinates of every point on the hyperbola is the same, and equal to aa. One point is therefore enough to pin down the whole function — unlike a line, which needs two.

The graph of an inverse proportion passes through A = (−4, 3). Give the formula, and check whether B = (6, −2) lies on it.

Asymptotes

Watch what happens to y=6xy = \tfrac{6}{x} as the argument shrinks towards zero:

xx110.10.10.010.010.0010.001
yy66606060060060006000

The values grow without bound. The line x=0x = 0 is a vertical asymptote: the curve hugs it ever more tightly and never touches it.

At the other end, for large arguments:

xx101010010010001000
yy0.60.60.060.060.0060.006

The values shrink towards zero without being zero. The line y=0y = 0 is a horizontal asymptote.

An asymptote is a line the curve approaches arbitrarily closely without ever reaching it. It does not belong to the graph — it is a reference line saying where the graph is headed.

The same idea returns later at the limit of a function, where "arbitrarily close" gets a precise definition, and at rational functions, where a third kind of asymptote — the oblique one — joins in.

The homographic function

A hyperbola can be translated like any other graph:

y=axp+qy = \frac{a}{x - p} + q

Such a function is called homographic. The translation by [p,q][p,\, q] takes the asymptotes with it:

x=pandy=qx = p \qquad \text{and} \qquad y = q
−6−4−20246810−6−4−202468xyy = 4/(x − 2) + 1
The hyperbola y = 4/x translated by [2, 1]. The crossing point of the asymptotes — the old origin — now sits at (2, 1), and the domain is every number except x = 2.

The domain is every real number except pp, because at x=px = p the denominator vanishes.

Vertex form

In problems, a homographic function usually arrives as a quotient of two linear expressions:

y=3x+5x2y = \frac{3x + 5}{x - 2}

In that spelling the asymptotes are invisible. To read them off, split as much of the denominator out of the numerator as possible:

3x+5=3(x2)+113x + 5 = 3(x - 2) + 11

and then divide term by term:

y=3(x2)x2+11x2=11x2+3y = \frac{3(x-2)}{x-2} + \frac{11}{x-2} = \frac{11}{x - 2} + 3

Now both numbers are written out: the asymptotes are x=2x = 2 and y=3y = 3.

In general:

ax+bxp=ap+bxp+a\frac{ax + b}{x - p} = \frac{ap + b}{x - p} + a

The horizontal asymptote sits at the height of the coefficient of xx in the numerator, and the vertical one at the zero of the denominator.

Write f(x) = (2x − 7)/(x + 1) in vertex form, and give its asymptotes and its domain.

Note that cancelling a common factor in rational expressions is a different operation: there a fraction is simplified, here its spelling changes while the function does not.

Where you meet it

Everywhere something is split into parts, or the product of two quantities is fixed:

  • t=svt = \dfrac{s}{v} — travel time at a given speed (see speed, distance and time); to convert the units quickly, the speed converter does it;
  • pV=constp \cdot V = \text{const} — Boyle's law for a gas at constant temperature;
  • I=URI = \dfrac{U}{R} — current at constant voltage;
  • cost per person=total costnumber of people\text{cost per person} = \dfrac{\text{total cost}}{\text{number of people}}.

In all four the graph falls ever more slowly — and that is the practical meaning of a horizontal asymptote: each additional unit brings a smaller gain than the one before.

Practice

The set checks the four steps of this lesson: the constant kk read off a single point, a value of a homographic function, the change to vertex form, and both asymptotes at once. For the asymptotes you type two numbers — the vertical one as xx, the horizontal one as yy. For the vertex form, copying the prompt back will not pass: the point is to change the spelling, not to repeat it.

Practice

Work through a set of exercises — they get harder as you go. At the end you'll see your score and the mistakes worth reviewing.

Exercise 1 of 8Score: 0
The k of y = k/x through the point: A(−2, −2)

Common mistakes

  • Confusing inverse proportion with direct — check what is constant: the ratio or the product.
  • Finding aa by dividing the coordinates — for a hyperbola a=xya = x \cdot y, not yx\tfrac{y}{x}.
  • Drawing the hyperbola as one stroke through zero — there are two branches and nothing joins them.
  • Treating an asymptote as part of the graph — it is a reference line, not a set of points of the function.
  • Reading the horizontal asymptote straight off ax+bxp\tfrac{ax+b}{x-p} — convert to vertex form first; the asymptote is y=ay = a, not y=by = b.
  • Forgetting the domainx=px = p is excluded and must be stated in the answer.

Formula card

Topic: Inverse proportion and the homographic function

  • Inverse proportion

    y=ax,a0y = \frac{a}{x}, \qquad a \neq 0

    domain: x \neq 0

  • The proportionality condition

    xy=ax \cdot y = a

    the product is constant — that is how a is found

  • Homographic function

    y=axp+qy = \frac{a}{x - p} + q

    a hyperbola translated by [p,\, q]

  • The asymptotes

    x=p,y=qx = p, \qquad y = q

    vertical and horizontal — approached, never reached

  • Vertex form

    ax+bxp=ap+bxp+a\frac{ax + b}{x - p} = \frac{ap + b}{x - p} + a

    a quotient of linear expressions as a translated hyperbola

−8−6−4−202468−8−6−4−202468xyy = 6/x
The hyperbola y = 6/x. Two branches, one in the first quadrant and one in the third, and two asymptotes: the axes themselves. The product of the coordinates of every point on the curve is 6.
−6−4−20246810−6−4−202468xyy = 4/(x − 2) + 1
The homographic function y = 4/(x − 2) + 1, that is the hyperbola y = 4/x translated by [2, 1]. The asymptotes travelled with it: the vertical one now stands at x = 2, the horizontal one at y = 1.

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