Intermediate level

Surface area of solids

Surface area is the area of a solid’s net — how much material it takes to cover it. See the formulas for a cuboid, a cylinder, a pyramid, a cone and a sphere, and why a cone and a pyramid are measured by the slant height rather than the height.

Before you start

This topic builds on earlier ideas. Before you start, it's worth working through the lessons below — they'll make everything click:

All formulas

  • The general rule

    A=Ab+AlA = A_b + A_l

    base area plus lateral area

  • Cuboid

    A=2(ab+bc+ac)A = 2(ab + bc + ac)

    three pairs of identical faces

  • Cube

    A=6a2A = 6a^2

    six identical squares

  • Cylinder

    A=2πr2+2πrh=2πr(r+h)A = 2\pi r^2 + 2\pi rh = 2\pi r(r + h)

    two circles and a rectangle with sides 2πr and h

  • Pyramid on a square base

    A=a2+2alA = a^2 + 2al

    l is the slant height of a face, not the height of the solid

  • Cone

    A=πr2+πrl=πr(r+l)A = \pi r^2 + \pi rl = \pi r(r + l)

    l is the slant height — from the apex to the rim of the base

  • Slant height of a cone

    l=r2+h2l = \sqrt{r^2 + h^2}

    from the Pythagorean theorem for the radius and the height

  • Sphere

    A=4πr2A = 4\pi r^2

    exactly four areas of a great circle

Volume says how much fits inside a solid. Surface area says how much material it takes to cover it — which is why we are back to square units.

Surface area is the area of the net

Cut a box along its edges and lay it flat. What you are left with is the net of the solid: a handful of ordinary plane figures whose areas you already know how to find. The surface area is their sum.

acb
A cuboid has six faces but only three different ones: the front a × c, the side b × c and the top a × b. Each appears twice.

The general rule is always the same:

A=Ab+AlA = A_b + A_l

where AbA_b is the base area (or the area of both bases) and AlA_l is the lateral area.

Cuboid and cube

The faces come in identical pairs, so it is enough to work out three of them and double the result:

A=2(ab+bc+ac)A = 2(ab + bc + ac)
Find the surface area of a cuboid with edges of 4 cm, 3 cm and 2 cm.

In a cube every face is the same, so the formula collapses to:

A=6a2A = 6a^2

For an edge of 3cm3\,\text{cm} that gives 69=54cm26 \cdot 9 = 54\,\text{cm}^2.

Cylinder

The net of a cylinder is two circles and one rectangle. The rectangle comes from unrolling the lateral surface, so its longer side is the circumference of the base, 2πr2\pi r, and its shorter side is the height hh.

rh
A cylinder: two circles of radius r plus a lateral surface which, cut open, is a 2πr by h rectangle.
A=2πr2two bases+2πrhlateral area=2πr(r+h)A = \underbrace{2\pi r^2}_{\text{two bases}} + \underbrace{2\pi rh}_{\text{lateral area}} = 2\pi r(r + h)
Find the surface area of a cylinder with a radius of 3 cm and a height of 5 cm. Take π ≈ 3.14.

Pyramid: the slant height, not the height

The net of a pyramid on a square base is a square and four triangles. The base of each triangle is the edge aa, and its height is the segment ll — the slant height of the face.

aH
The height H runs inside the solid, perpendicular to the base. The slant height lies on a lateral face and is longer than H — and it is the one the area formula takes.

One triangle has area 12al\frac{1}{2}al, and there are four of them:

A=a2+412al=a2+2alA = a^2 + 4 \cdot \frac{1}{2}al = a^2 + 2al

The slant height follows from the Pythagorean theorem — it is the hypotenuse of a right triangle with legs HH and a2\frac{a}{2}:

l=H2+(a2)2l = \sqrt{H^2 + \left(\frac{a}{2}\right)^2}
A pyramid has a square base of side 6 cm and a height of 4 cm. Find its surface area.

Cone: the slant height again

In a cone the part played by the pyramid's slant height is played by the slant height ll — the segment from the apex to the rim of the base. Unrolled, the lateral surface is a sector of a circle of radius ll, and its area is πrl\pi rl.

rhl
The radius r, the height h and the slant height l form a right triangle, so l = √(r² + h²).
A=πr2+πrl=πr(r+l)A = \pi r^2 + \pi rl = \pi r(r + l)

The slant height is almost never given alongside the height — it has to be worked out:

l=r2+h2l = \sqrt{r^2 + h^2}
A cone has a base radius of 3 cm and a height of 4 cm. Find its surface area. Take π ≈ 3.14.

Sphere

A sphere cannot be laid out flat — every map of the world is proof of that. Even so its surface area is surprisingly simple: exactly four areas of a circle of the same radius.

A=4πr2A = 4\pi r^2
rO
A sphere of radius r. Its surface area is four areas of a great circle — a circle of that same radius r.
Find the surface area of a sphere of radius 3 cm. Take π ≈ 3.14.

Units

Surface area is still an area, so it is measured in cm2\text{cm}^2, m2\text{m}^2 and hectares — not in cm3\text{cm}^3. When converting units of area the length factor is squared: 1m2=10,000cm21\,\text{m}^2 = 10{,}000\,\text{cm}^2. For actual values, our area converter will do the arithmetic.

Exercises

If the question does not name a unit, type it together with the answer, e.g. 52 cm². If the unit is given in brackets (because π\pi shows up in the answer), type the number alone, rounded to two decimal places. Slant heights are always given in the question — you never have to derive one here.

Practice

Work through a set of exercises — they get harder as you go. At the end you'll see your score and the mistakes worth reviewing.

Exercise 1 of 8Score: 0
Surface area of a cuboid: a = 4 cm, b = 6 cm, c = 6 cm

Common mistakes

  • The height instead of the slant height — surface area takes the segment lying on a lateral face, which is longer than the height.
  • Forgetting the cylinder's second base — there are two circles, hence 2πr22\pi r^2.
  • Counting a base that is not there — a sphere has no base, and a cone has only one.
  • A cubic unit52cm252\,\text{cm}^2, not 52cm352\,\text{cm}^3; the cube belongs to volume.
  • Mixing up the sphere's formulas4πr24\pi r^2 is the area, 43πr3\frac{4}{3}\pi r^3 is the volume; the area has the radius squared.
  • Taking the lateral area for the wholeAlA_l is only a part; the general rule is A=Ab+AlA = A_b + A_l.

Formula card

Topic: Surface area of solids

  • The general rule

    A=Ab+AlA = A_b + A_l

    base area plus lateral area

  • Cuboid

    A=2(ab+bc+ac)A = 2(ab + bc + ac)

    three pairs of identical faces

  • Cube

    A=6a2A = 6a^2

    six identical squares

  • Cylinder

    A=2πr2+2πrh=2πr(r+h)A = 2\pi r^2 + 2\pi rh = 2\pi r(r + h)

    two circles and a rectangle with sides 2πr and h

  • Pyramid on a square base

    A=a2+2alA = a^2 + 2al

    l is the slant height of a face, not the height of the solid

  • Cone

    A=πr2+πrl=πr(r+l)A = \pi r^2 + \pi rl = \pi r(r + l)

    l is the slant height — from the apex to the rim of the base

  • Slant height of a cone

    l=r2+h2l = \sqrt{r^2 + h^2}

    from the Pythagorean theorem for the radius and the height

  • Sphere

    A=4πr2A = 4\pi r^2

    exactly four areas of a great circle

acb
A cuboid with edges a, b, c. It has six faces, but they come in identical pairs — hence A = 2(ab + bc + ac).
rhl
A cone: base radius r, height h and slant height l. Surface area takes the slant height: A = πr(r + l).

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